1.
INTELSAT stands?
a) International
Telecommunications Satellite
b)
India Telecommunications Satellite
c)
Inter Telecommunications Satellite
d) None of the above
2.
Kepler’s first law states?
a) The path followed by
a satellite around the primary will be an ellipse.
b) The path followed by a satellite around
the primary will be a circle.
c) The path followed by a satellite around
the primary will be a sphere
d) None of the above
3.
Kepler’s second law states?
a) If t2-t1=t4-t3, then A12=A34.
b) If t2+t1 = t4+t3, then A12=A34.
c) If t2/t1=t4/t3, then A12=A34.
d) All of above
4.
For an elliptical orbit?
a) 0<e< 1
b) 0= e
c) 1= e
d) None of the above
5. The orbital
period in seconds?
a) P =2π / n.
b) P=2
π / n2
c) P=
π / n
d)
None of the above
6.
What is application of satellite systems?
a) whether forecasting
b) Terrestrial communication
c) point to point communication
d) None of the above
7.
A random satellite moves in
a) Random path
b) Polar orbit
c) Geostationary orbit
d)
Equatorial plane
8.
Number of geo-stationary orbit is
a) 0
b) 1
c) infinite
d) Cannot be determined
9.
Define Polar-orbiting Satellites.
a) Polar orbiting Satellites orbit the earth
in such a way as to cover the north & south Polar Regions.
b) Orbiting Satellites orbit the earth in
such a way as to cover the east & west Polar Regions
c) Either (a) & (b)
d)
None of the above
10.
Atmospheric drag has negligible effect on
a) Geostationary
satellites
b) MEO
c) LEO
d) None of these
11.
In analog technique of modulation in satellite, the most commonly employed
system is
a) AM
b) FM
c) PAM
d) PWM
12.
The angle subtended by earth at a geostationary communication satellite is
nearly
a)
66.5
b) 47.34
c) 17.34
d) 7.34
13.
The main advantage of satellite communication is
a) Low cost
b) Low distortion
c) High reliability
d) High band width
14.
Geostationary satellites are located at a height of
a) 3600 km from earth’s surface
b) 36000 km from earth’s surface
c) 360,000 km from earth’s surface
d) 3600,000 km from earth’s surface
15.
The velocity of a geostationary satellite is nearly
a) 1255 km/hr
b) 6757 km/hr
c) 9422 km/hr
d) 12644 km/hr
16.
A synchronous satellite orbits the earth once in
a) 24 hours
b) 12 hours
c) 6 hours
d) 1 hours
17.
Calculate the radius of a circular orbit for which the period is 1 day?
a) 42.241Km
b) 42.241m
c) 4.241Km
d) 2.241Km
18.
The order of optical frequencies is
a) MHz
b) GHz
c) KHz
d) TeraHz
19.
Following is not a usual classification of optical fibre
a) Single-mode step index
b) Single mode graded index
c) Multimode step index
d) Multimode graded index
20.
A certain optical fiber has a refractive index of clad
(n1) =1.40 and that of core
(n2) =1.05.Its Numerical aperture will be
a) 0.8575
b) 0.9260
c) 0.3500
d) 0.1585
21.
Light travels in optical fiber by which mechanism
a) Refraction
b) Reflection
c) Scattering
d) Total Internal Reflection
22.
Losses in optical fiber can be caused by which of the following
1) Impurities
2) Micro bending
3) Stepped-Index operation
a) 1 & 3
b) 2&3
c)
1&2
d) 3 only
23.
The optical fiber uses ……..portion of EM spectrum
a) IR
b) VHF
c) UHF
d) HF
24.
A glass fiber has refractive indices n1 of 1.5 and n2 of 1.Assuming
c=3x108 m/s, the multipath
time dispersion will be
a) 2.5 ns/m
b) 2.5µs/m
c) 5ns/m
d) 5 µs/m
25.
Dispersion in an optical fiber used in a
communication link is of which type?
a) Angular Dispersion
b) Modal dispersion
c) Chromatic dispersion
d) Dispersion arising due to structural
irregularities in the fiber
26. The numerical
aperture (NA) and acceptance angle are related as
a)
NA =sinӨ
b) NA=sin-1Ө
c) NA= (1-sin2Ө)1/2
d) None
27.
A single mode fiber doesn’t suffer which type of dispersion?
a) Waveguide dispersion
b) Material Dispersion
c) Intermodal Dispersion
d) Polarization mode Dispersion
28.
A certain optical fiber has a refractive index of clad (n1) =1.40.its
numerical apertures is 0.9260 then find
refractive index of core (n2)
a) 1.50
b) 1.05
c) 1.005
d) None